The radius of a right circular cone is 3 cm and its height is 4 cm

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The radius of a right circular cone is 3 cm and its height is 4 cm. The curved surface of the cone will be

A$$12 \pi \text{ sq.cm}$$

B$$15 \pi \text{ sq.cm } $$

C$$18 \pi \text{ sq.cm }$$

D$$ 21 \pi \text{ sq.cm} $$

balakrishna ? Jul 2 '2017 at 11:27

Answer is \(15 \pi \text{ sq.cm }\)

Explanation:

Slant height of the cone \(l = \sqrt{r^2+h^2}\)

= \(\sqrt{3^2+4^2}\)

= \(\sqrt{9+16}\)

=\(\sqrt{25}=5 \text { cm}\)

\(\therefore\) Area of the curved surface

= \(\pi rl \)

\(=\pi \times3\times5\)

\(= 15 \pi \text{ sq.cm}\)

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The sides of a triangle are in the ratio 3:5:7 and its perimeter is 30 cm.

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The sides of a triangle are in the ratio 3:5:7 and its perimeter is 30 cm. The length of the greatest side of the triangle in cm is

A6

B10

C14

D16

ranjith ? Jul 2 '2017 at 11:7

Answer is 14

Explanation:

Let the sides of the triangle be 3x,5x and 7x units.

According to the questions

3x+5x+7x=30

=> 15x = 30

\(x = \frac{30}{15} =2\)

Largest side = 7x

\(= 7 \times 2\)

=14

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A horse is tied to a peg hammered at one of the corner of a rectangular grass field of 40 m by 24 m by a rope 14 m long. Over how much area of the field can the horse graze ?

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A horse is tied to a peg hammered at one of the corner of a rectangular grass field of 40 m by 24 m by a rope 14 m long. Over how much area of the field can the horse graze ?

A154 sq m

B308 sq m

C240 sq m

D480 sq m

ramesh ? Jul 2 '2017 at 10:55

Answer is 154 sq m

Explanation:

Area of part grazed by horse = \(\frac{1}{4}\)

\(\therefore\) Required Area = \(\frac{1}{4}\pi r^2\)

\(= \frac{1}{4}*(3.14)*(14^2) = 153.86 \)

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A number consists of two digits whose sum is 9. If 9 is subtracted from the number, the digits interchange their places. The number is?

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A number consists of two digits whose sum is 9. If 9 is subtracted from the number, the digits interchange their places. The number is?

A44

B54

C62

D53

rajavardhan ? Jul 2 '2017 at 10:29

Answer is 54

Explanation:

Let us assume, x and y are the two digits of a two-digit number.
Therefore, the two-digit number = 10x + y and the reversed number = 10y + x

Given:
x + y = 9 ---------1

Also given:
10x + y - 9 = 10y + x
9x - 9y = 9
x - y = 1 -----------2

Adding equation 1 and equation 2
2x = 10
x = 5

Therefore, y = 9 - x = 9 - 5 = 4

Therefore, the two digit number = 10x + y = 10*5 + 4 = 54

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By selling an article for Rs. 40, there is loss of 40%. By selling it for Rs. 80 there is

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By selling an article for Rs. 40, there is loss of 40%. By selling it for Rs. 80 there is

AGain of 20%

BLoss of 10%

CLoss of 20%

DGain of 10%

m p rao ? Mar 12 '2019 at 9:46

BY SELLING AN ARTICLE FOR Rs. 40, there is a loss of 40%. What will be gain by selling it for Rs. 80?

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On selling three articles at the cost of four article, there will be profit of—

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On selling three articles at the cost of four article, there will be profit of—

A25%

B $$33\frac{1}{3}%$$

C$$ 37 \frac{1}{2}%$$

D40%

praksha ? Jul 1 '2017 at 16:23

Answer is \(33\frac{1}{3}\text{%}\)

Explanation:

Let the CP of each article be Rs.1

\(\therefore\) CP of 3 article = Rs.3

\(\)\(\therefore\)SP of 3 articles = Rs.4

\(\therefore\) Gain % = \(\frac{4-3}{3} \times 100\)

\(= \frac{100}{3} = 33\frac{1}{3}\text{%}\)

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Where did the dance form “Mohini Attam” develop?

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Where did the dance form “Mohini Attam” develop?

AManipur

B Kerala

C Karnataka

D Tamil Nadu

No answer description available for this question. Let us discuss.

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