There is a rectangular tank of length 180 m and breadth 120

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There is a rectangular tank of length 180 m and breadth 120 m in a circular field. If the area of the land portion of the field is 40000 m^2, what is the radius of the field? (take Π = 22/7 )

A130 m

B135 m

C140 m

D145 m

test@gmail ? Oct 17 '2017 at 19:42

Answer is : Option C

Explanation :

Total area of the field  =\( [(180 x 120) + 40000] \text{ }m^2\)

= \((21600 + 40000) \text{ }m^2 = 61600 \text{ }m^2\)

\(\therefore \pi R^2 = 61600\)

⇔ \(R^2\) =\(\Big(61600×\frac{7}{22}\Big)\) = 400 x 7 x 7) m

 R = 20 x 7 =  140 m.

 

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A trader marked the price of his commodity so as to include

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A trader marked the price of his commodity so as to include a profit of 25%. He allowed discount of 16% on the marked price. His actual profit was

A5%

B9%

C16%

D25%

Nithin K ? Dec 4 '2016 at 20:55

Answer : 5%

Explanation:

Let C.P. be Rs. 100. Then, marked price = Rs. 125  

\(\text{S.P = 84% of Rs. 125 }= Rs. \Big(\frac{84}{100} \times 125 \Big) = Rs.105\)

\(\therefore Profit = (105 - 100) \% = 5\%  \)

 

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Of 208 + 786 = 2000 -?8

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A112

B148

C184

D124

No answer description available for this question. Let us discuss.

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1354 + 1184 = ? % of 5640

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1354 + 1184 = ? % of 5640

A36

B42

C45

D52

Nithin K ? Dec 4 '2016 at 20:32

Answer: 45

Explanation:

\(1354 + 1184 = \text{? % of 5640}\)

\(2538 \text{ = ? % of 5640}\)

\(2538 = \frac{5640 \times x}{100} \)

\(x = \frac{2538 \times 100}{5640}\)

\(x= 45\)

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45% of 1200 = 54% of ?

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45% of 1200 = 54% of ?

A1080

B1320

C1240

D1000

Nithin K ? Dec 4 '2016 at 20:16

Answer: 1000

Explanation:
\(45\% \text{ of 1200 = 54% of x }\)
\(45 \times \frac{1200}{100} = 54 \times \frac{x}{100}\)

\(45 \times 12 = 0.54 \times x\)

\(x = \frac{45 \times 12}{0.54} = \frac{540}{0.54}\)

\(x = \frac{54000}{54} = 1000\)

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Of the two numbers, 48 percent of first number is 60 percent

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Of the two numbers, 48 percent of first number is 60 percent of the second number. What is the respective ratio of the first number to the second number?

A4:7

B3:4

C5 : 4

DCannot be determined

Nithin K ? Dec 4 '2016 at 19:59

Answer : 5 : 4

Explanation:

Let the numbers be x and y.

48% of x = 60% of y

\(⇒ \frac{x}{y} = \frac{60}{48} = \frac{10}{8} = \frac{5}{4}\)

\(\therefore x : y = 5 : 4\)

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The HCF of two numbers is 15 and their LCM is 300. If one of

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The HCF of two numbers is 15 and their LCM is 300. If one of the numbers is 60, the other is

A50

B75

C65

D100

Nithin K ? Dec 4 '2016 at 19:23

Answer : 75

Explanation:

\(\text{ First number } \times \text{ Second number }= \text{ LCM } \times \text{ HCF}\)

\(\therefore \text{ Second number }= \frac{ \text{ LCM } \times \text{ HCF}}{ \text{ First number } }\)

Given, First Number = 60, HCF =15, LCM = 300

\(\therefore \text{ Second number }= \frac{ \text{ 300 } \times \text{ 15 }}{ \text{60 } }\)

\(\therefore \text{ Second number = 75}\)

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