If the ages of P and R are added to twice the age of Q, the total becomes 59; if the ages of Q and R are added to thrice age of P, the total becomes 68 and if the age of P is added to thrice the age of Q and thrice the age of R, the total becomes 108. What is the age of P ?

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BANK PO Exam (SBI) 1999 click here to view all questions

If the ages of P and R are added to twice the age of Q, the total becomes 59; if the ages of Q and R are added to thrice age of P, the total becomes 68 and if the age of P is added to thrice the age of Q and thrice the age of R, the total becomes 108. What is the age of P ?

A15 years

B19 years

C17 years

D12 years

Akilesh Kharvi ? Jun 28 '2020 at 11:28

Correct answer is: 12 years

Explanation:

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The average height of 16 students is 142 cm. If the height of the teacher is included, the average height increases by 1 cm. The height of the teacher is

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The average height of 16 students is 142 cm. If the height of the teacher is included, the average height increases by 1 cm. The height of the teacher is

A156 cm

B159 cm

C158 cm

D157 cm

Akilesh Kharvi ? May 27 '2017 at 12:34

Answer is : 159 cm

Explanation:

Height of teacher \(= 143 \times 17 - 142 \times 16\)

= 159 cm

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The present age of Romila is one fourth of that of her father. After 6 years the father’s age will be twice the age of Kapil. If Kapil celebrated fifth birth day 8 years ago, What is Romils’s present age ?

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The present age of Romila is one fourth of that of her father. After 6 years the father’s age will be twice the age of Kapil. If Kapil celebrated fifth birth day 8 years ago, What is Romils’s present age ?

A7 years

B7.5 years

C8 years

D8.5 years

Akilesh Kharvi ? May 27 '2017 at 12:23

Answer is : 7.5 years

Explanation:

Kapil’s present age = 12 years

After 6 years, Kapil’s age = 18 years

Father’s present age = 18 × 2 - 6= 30 years

Romlla’s present age = \(\frac{1}{4}× 30 = 7.5 years\)

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The average of the 9 consecutive positive integers is 63. The product of the largest and smallest integers is

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The average of the 9 consecutive positive integers is 63. The product of the largest and smallest integers is

A3935

B3953

C3853

D3835

undefined ? Jan 29 '2018 at 21:48

if average of 9 consecutive positive integers is 63 then its middle number is 63, so number series becomes
(63-4), (63-3), (63-2), (63-1), 63, (63+1), (63+2), (63+3), (63+4)

59, 60, 61, 62, 63, 64, 65, 66, 67

Fifth number = 63

Smallest number = 59

Largest number = 67

Required product = 59 × 67 = 3953

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The average height of 27 persons was recorded as 162 cm. If the height of Shreyas was deleted from the observation, the aver-age height reduced by 1 cm. What was Shreyas’ height ?

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The average height of 27 persons was recorded as 162 cm. If the height of Shreyas was deleted from the observation, the aver-age height reduced by 1 cm. What was Shreyas’ height ?

A188 cm.

B226 cm.

C179 cm.

D186 cm.

Nithin K ? May 26 '2017 at 20:33

Answer is 188 cm.

Explanation:

Height of Shreyas

= 162 × 27 -  161 × 26

= 188 cm

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The average of four consecutive even numbers P, Q, R and S respectively (in increasing order) is 51. What is the product of P and R ?

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The average of four consecutive even numbers P, Q, R and S respectively (in increasing order) is 51. What is the product of P and R ?

A2592

B2400

C2496

D2808

Nithin K ? May 26 '2017 at 20:4

Answer is : 2496

Explanation:

 x + x + 2 + x + 4 + x + 6= 4 × 51

4x + 12 = 204

4x = 204- 12

4x = 192

x = 48 =P

R = 48 + 4 = 52

P × R = 48 × 52

= 2496

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Farah was married 8 years ago. Today her age is 1 (2/7) times to that at the time of marriage. At present her daughter's age is 1/6 th of her age.What was her daughter's age 3 years ago ?

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Farah was married 8 years ago. Today her age is 1 (2/7) times to that at the time of marriage. At present her daughter's age is 1/6 th of her age.What was her daughter's age 3 years ago ?

A6 years

B7 years

C3 years

DCannot be determined

Nithin K ? May 26 '2017 at 19:12

Answer is 3 years

Explanation

Let Farah’s age 8 years ago be x years

Farah’s present age = (x + 8) years

\(x + 8 = \frac{9x}{7}\)

7x + 56 = 9x

2x = 56

x = 28

Farah’s present age= 28 + 8 = 36 years

Her daughter’s age 3 years ago

\(= 36 \times \frac{1}{6} - 3 = 3 \text{ years }\)

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