Farah was married 8 years ago. Today her age is 1 (2/7) times to that at the time of marriage. At present her daughter's age is 1/6 th of her age.What was her daughter's age 3 years ago ?

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Farah was married 8 years ago. Today her age is 1 (2/7) times to that at the time of marriage. At present her daughter's age is 1/6 th of her age.What was her daughter's age 3 years ago ?

A6 years

B7 years

C3 years

DCannot be determined

Nithin K ? May 26 '2017 at 19:12

Answer is 3 years

Explanation

Let Farah’s age 8 years ago be x years

Farah’s present age = (x + 8) years

\(x + 8 = \frac{9x}{7}\)

7x + 56 = 9x

2x = 56

x = 28

Farah’s present age= 28 + 8 = 36 years

Her daughter’s age 3 years ago

\(= 36 \times \frac{1}{6} - 3 = 3 \text{ years }\)

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Answer is 3 years Explanation Let Farah’s age 8 years ago be x years Farah’s present age = (x + 8) years \(x + 8 = \frac{9x}{7}\) 7x + 56 = 9x 2x = 56 x = 28 Farah’s present age= 28 + 8 = 36 years Her daughter’s age 3 years ago \(= 36 \times \frac{1}{6} - 3 = 3 \text{ years }\) Nithin K ? answered May 26 '2017 at 19:12 All Comments

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