The wheat sold by a grocer contained 10% low quality wheat. What quantity of good quality wheat should be added to 150 kgs of wheat so that the percentage of low quality wheat becomes 5%?

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BANK PO Exam (SBI) 2002 click here to view all questions

The wheat sold by a grocer contained 10% low quality wheat. What quantity of good quality wheat should be added to 150 kgs of wheat so that the percentage of low quality wheat becomes 5%?

A150 kgs

B135 kgs

C50 kgs

D85 kgs

Nithin ? undefined

Correct answer is: 150 kgs

Explanation:

Good quality content in 150 kgs. of wheat = 90% of 150 = 135 kgs.
In new mixture, low quality wheat is 5%, so good quality wheat 95%
and 5% of the new mixture = 15 kgs.

Therefore, New mixture = \(\frac{15 \times 100}{5}\) = 300 kg.

Therefore, Good quality of wheat added =  \(\left(300 - 150\right)\)= 150 kg.

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In 1 kg of a mixture of sand and iron, 20% is iron .How such sand should be added so that the proportion of iron becomes 5%?

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BANK PO Exam (SBI) 1999 click here to view all questions

In 1 kg of a mixture of sand and iron, 20% is iron .How such sand should be added so that the proportion of iron becomes 5%?

A3 kg

B4 gms

C5 gms

D6 kg

Nithin ? undefined

Correct answer is: 3 kg

Explanation:

Total mixture of sand and iron = 1 kg

Quantity of iron = \(\frac{20}{100} \times 1 = 0.2 \text{ kg}\)

Let x kg of sand should be added, thus total iron in the mixture

\(\implies 0.2=\frac{5}{100} \times (x+1)\)

\(\implies 4=x+1\)

\(\implies x=4-1=3 \text{ kg}\)

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In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm)

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BANK PO Exam (Indian Overseas Bank) 2009 click here to view all questions

In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm)

A 80%

B70%

C75%

D 62%

Nithin ? undefined

Correct answer is: 80%
Explanation:

Water in 60 gm mixture= \(60 \times \frac{75}{100}\) = 45 gm. and Milk = 15 gm.

After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and weight of a mixture = 60 + 15 = 75 gm.

So % of water = \(100 \times \frac{60}{75}\) = 80%

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The cost of making an article is divided between materials. labour and overheads in the ratio of 3 : 4 : 1. If the material costs Rs.234, then the labour cost is:

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INSURANCE EXAMS (NICL) 2013 click here to view all questions

The cost of making an article is divided between materials. labour and overheads in the ratio of 3 : 4 : 1. If the material costs Rs.234, then the labour cost is:

ARs.176

BRs.312

CRs.78

DRs.390

Nithin ? undefined

Correct answer is: Rs.312

Explanation:

Materials : labour : Overheads = 3 : 4 : 1
Sum of ratios = 3 + 4 +1 = 8
If the total cost be Rs. x, then

\(= \frac{3x}{8}=234 \)

\(\implies \Large x = \frac{234 \times 8}{3} \) = Rs.624

Therefore, Labour cost = \(\frac{4}{8} \times 624\)

= Rs.312

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If A : B = 1 : 3, B : C = 5 : 7, C : D = 9 : 7, then A : B : C : D = ?

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If A : B = 1 : 3, B : C = 5 : 7, C : D = 9 : 7, then A : B : C : D = ?

A15 : 45 : 63 : 49

B15 : 49 : 45 : 63

C45 : 15 : 63 : 49

D49 : 15 : 45 : 63

Nithin ? undefined

Correct answer is: 15 : 45 : 63 : 49

Explanation:

A : B = 1 : 3 = 15 : 45

B : C = 5 : 7 = (5 × 9) : (7 × 9) = 45 : 63

C : D = 9 : 7 = (9 × 7) : (7 × 7) = 63 : 49

∴ A : B : C : D = 15 : 45 : 63 : 49

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Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:

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Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:

A1 : 3

B3 : 2

C3 : 4

DNone of these

Nithin ? undefined

Correct answer is: 3 : 2

Explanation:

\(\eqalign{ & {\text{Let}}\,{\text{the}}\,{\text{speeds}}\,{\text{of}}\,{\text{the}}\,{\text{two}}\,{\text{trains}}\,{\text{be}}\,x\,{\text{m/sec}} \cr & {\text{and}}\,y\,{\text{m/sec}}\,{\text{respectively}}. \cr & {\text{Then,}}\,{\text{length}}\,{\text{of}}\,{\text{the}}\,{\text{first}}\,{\text{train}} = 27x\,{\text{metres}}, \cr & {\text{and}}\,{\text{length}}\,{\text{of}}\,{\text{the}}\,{\text{second}}\,{\text{train}} = 17y\,{\text{metres}}. \cr & \therefore \frac{{27x + 17y}}{{x + y}} = 23 \cr & \Rightarrow 27x + 17y = 23x + 23y \cr & \Rightarrow 4x = 6y \cr & \Rightarrow \frac{x}{y} = \frac{3}{2} \cr} \)

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The average score of a class of boys and girls in an examination is A. The ratio of boys and girls in the class is 3 : 1. If the average score of the boys is A + 1, the average score of the girls is-

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The average score of a class of boys and girls in an examination is A. The ratio of boys and girls in the class is 3 : 1. If the average score of the boys is A + 1, the average score of the girls is-

AA - 1

BA - 3

CA + 1

DA + 3

Nithin ? undefined

Correct answer is: A - 3

Explanation:

Let the number of boys and girls in the class be 3x and x respectively.
Let the average score of the girls be y.
Then,
⇒ 3x (A + 1) + xy = (3x + x) A
⇒ 3 (A + 1) y = 4A
⇒ y = A - 3

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