In 1 kg of a mixture of sand and iron, 20% is iron .How such sand should be added so that the proportion of iron becomes 5%?

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BANK PO Exam (SBI) 1999 click here to view all questions

In 1 kg of a mixture of sand and iron, 20% is iron .How such sand should be added so that the proportion of iron becomes 5%?

A3 kg

B4 gms

C5 gms

D6 kg

Nithin ? undefined

Correct answer is: 3 kg

Explanation:

Total mixture of sand and iron = 1 kg

Quantity of iron = \(\frac{20}{100} \times 1 = 0.2 \text{ kg}\)

Let x kg of sand should be added, thus total iron in the mixture

\(\implies 0.2=\frac{5}{100} \times (x+1)\)

\(\implies 4=x+1\)

\(\implies x=4-1=3 \text{ kg}\)

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Correct answer is: 3 kg Explanation: Total mixture of sand and iron = 1 kg Quantity of iron = \(\frac{20}{100} \times 1 = 0.2 \text{ kg}\) Let x kg of sand should be added, thus total iron in the mixture \(\implies 0.2=\frac{5}{100} \times (x+1)\) \(\implies 4=x+1\) \(\implies x=4-1=3 \text{ kg}\) Nithin ? answered undefined All Comments

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