Vishwas borrowed a total amount of Rs. 30,000 part of it on simple interest, rate of 12 p.c.p.a. and remaining on simple interest rate of 10 p.c.p.a. If at the end of 2 years he paid in all Rs. 36,480 to settle the loan amount, what was the amount borrowed at 12 p.c.p.a.?

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BANK PO Exam (Indian Overseas Bank) 2008 click here to view all questions

Vishwas borrowed a total amount of Rs. 30,000 part of it on simple interest, rate of 12 p.c.p.a. and remaining on simple interest rate of 10 p.c.p.a. If at the end of 2 years he paid in all Rs. 36,480 to settle the loan amount, what was the amount borrowed at 12 p.c.p.a.?

A Rs. 16000

B Rs. 18000

CRs. 17500

DRs. 12000

upendra ? undefined

Correct answer is: Rs. 12000

Explanation:

Let the sum borrowed at 12% p.a. be Rs. x
and that borrowed at 10% p.a. be Rs. (30000 - x)
S.I. at the end of 2 years
= Rs. (36480 - 30000)
= Rs. 6480

\(\eqalign{ & \therefore \left( {\frac{{x \times 12 \times 2}}{{100}}} \right) + \left[ {\frac{{\left( {30000 - x} \right) \times 10 \times 2}}{{100}}} \right] = 6480 \cr & \Leftrightarrow 24x + 600000 - 20x = 648000 \cr & \Leftrightarrow 4x = 48000 \cr & \Leftrightarrow x = 12000. \cr}\)

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A certain amount earns simple Interest of Rs. 1,750/- after 7 years. Had the interest been 2% more, how much more interest would it have earned ?

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BANK PO Exam (Canara Bank) 2003 click here to view all questions

A certain amount earns simple Interest of Rs. 1,750/- after 7 years. Had the interest been 2% more, how much more interest would it have earned ?

ARs. 35/-

BRs. 350/-

CRs. 245/-

DCannot be determined

nithin ? undefined

To find out how much more interest would have been earned if the interest rate were 2% more,
we need to calculate the interest earned at the original rate and the interest earned at the increased rate.
Let's denote: - Original interest rate = \(R\) (in percentage)
- Principal amount = \(P\)
- Time period = \(T\) (in years)
- Original interest earned = \(I_1\)
- Interest earned at the increased rate = \(I_2\)
Given: - \(I_1 = Rs. 1,750\) - \(T = 7\) years We can use the formula for simple interest: \[I = \frac{P \times R \times T}{100}\] For the original interest rate: \[1750 = \frac{P \times R \times 7}{100}\] \[P \times R = \frac{1750 \times 100}{7}\] \[P \times R = 25000\] Now, if the interest rate were increased by 2%, the new rate would be \(R + 2\) (in percentage). For the increased interest rate: \[I_2 = \frac{P \times (R + 2) \times 7}{100}\] The difference in interest would be: \[\text{Difference} = I_2 - I_1\] Let's calculate \(I_2\) and the difference: \[I_2 = \frac{P \times (R + 2) \times 7}{100}\] \[= \frac{P \times (R \times 7 + 2 \times 7)}{100}\] \[= \frac{P \times (25000 + 2 \times 7)}{100}\] \[= \frac{P \times (25000 + 14)}{100}\] \[= \frac{P \times 25014}{100}\] \[= 250.14P\] Now, calculate the difference: \[\text{Difference} = I_2 - I_1\] \[= 250.14P - 1750\] We have the value of \(P\) from the earlier calculation: \[P \times R = 25000\] \[R = \frac{25000}{P}\] Substitute this value of \(R\) into the difference equation: \[\text{Difference} = 250.14P - 1750\] \[= 250.14P - 1750\] \[= 250.14 \times \frac{25000}{R} - 1750\] Now, we need to determine the value of \(R\) (original interest rate). However, it's not given, so we can't determine the exact difference. Therefore, the answer is option D: Cannot be determined.

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A seller allows a discount of 5% on a watch. If he allows a discount of 7%, he earns Rs.15 less in the profit. What is the marked price?

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A seller allows a discount of 5% on a watch. If he allows a discount of 7%, he earns Rs.15 less in the profit. What is the marked price?

ARs.697.50

BRs.712.50

CRs.750

DRs.817.50

Nithin ? undefined

Correct answer is: Rs.750

Explanation:

lf the marked price be x then,

\(= \left(7-5\right)\) % of x = 15

\(\implies \frac{x \times 2}{100} = 15\)

\(\implies \frac{1500}{2} = \text{ Rs.750}\)

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A dealer offers a discount of 10% on the marked price of an article and still makes a profit of 20%. If its marked price is Rs.800, then the cost price is:

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A dealer offers a discount of 10% on the marked price of an article and still makes a profit of 20%. If its marked price is Rs.800, then the cost price is:

ARs.600

BRs.700

CRs.800

DRs.900

Nithin ? undefined

Correct answer is: Rs.600

Explanation:

Marked Price = Rs.800
S.P. = \(\frac{800 \times 90}{100}\)= Rs.720

Therefore, C.P. = \(= \frac{100}{120} \times 720\)

= Rs.600

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The difference between a discount of 40% on Rs.500 and two successive discounts of 36% and 4% on the same amount is

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The difference between a discount of 40% on Rs.500 and two successive discounts of 36% and 4% on the same amount is

ARs.0

BRs.2

CRs.1.93

DRs.7.20

Nithin ? undefined

Correct answer is: Rs.7.20

Explanation:

Discount of 40% on Rs.500

\(= \frac{500 \times 40}{100}\)= Rs.200

and single discount per cent equivalent to 36% and 4%

\(= \left(r_{1}+r_{2}-\frac{r_{1}r_{2}}{100}\right)\%\)

\(= 36+4-\frac{36 \times 4}{100}=40-1.44 = \text{38.56%}\)

Therefore, Discount by 38.56% on 500

\(= \frac{38.56 \times 500}{100} = \text{Rs.192.80}\)

Hence, required difference = (200 - 192.80} = Rs.7. 20

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A T-shirt marked at Rs. 400 is sold for Rs.360. The rate of discount is

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INSURANCE EXAMS (NICL) 2013 click here to view all questions

A T-shirt marked at Rs. 400 is sold for Rs.360. The rate of discount is

A12%

B10%

C15%

D17%

Nithin ? undefined

Correct answer is: 10%

Explanation:

Discount

\(= \frac{400-360}{400} \times 100\)

= 10%

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A shopkeeper marks his goods at such a price that after allowing a discount of 12.5 % on the marked price, he still earns a profit of 10%. The marked price of an article which costs him Rs. 4900 is -

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A shopkeeper marks his goods at such a price that after allowing a discount of 12.5 % on the marked price, he still earns a profit of 10%. The marked price of an article which costs him Rs. 4900 is -

ARs. 5390

BRs. 5490

CRs. 6160

DRs. 6260

Nithin ? undefined

Correct answer is: Rs. 6160

Explanation:

\(\eqalign{ & {\text{C}}{\text{.P}}{\text{. = Rs}}{\text{. 4900}}{\text{.}} \cr & {\text{S}}{\text{.P}}{\text{. = 110}}\% {\text{ of Rs}}{\text{.4900}} \cr & {\text{ = Rs}}{\text{.}}\left( {\frac{{110}}{{100}} \times 4900} \right) \cr & = {\text{Rs}}{\text{. 5390}}{\text{.}} \cr & {\text{Let marked price be Rs}}{\text{.}}x \cr & {\text{Then,}} \cr & {\text{ = 87}}\frac{1}{2}\% {\text{ of }}x{\text{ = 5390}} \cr & \Rightarrow \left( {\frac{{175}}{2} \times \frac{1}{{100}} \times x} \right) = 5390 \cr & \Rightarrow x = \left( {\frac{{5390 \times 8}}{7}} \right) = 6160 \cr & \therefore {\text{Marked price}} = {\text{Rs}}{\text{.6160}} \cr}\)

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