The simple interest accrued on a sum of certain principal is Rs 1,200 in four years at the rate of 8 p.c.p.a. What would be the simple interest accrued on thrice of that principal at the rate of 6 p.c.p.a. in 3 years ?

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BANK PO Exam (Oriental Bank of Commerce) 2010 click here to view all questions

The simple interest accrued on a sum of certain principal is Rs 1,200 in four years at the rate of 8 p.c.p.a. What would be the simple interest accrued on thrice of that principal at the rate of 6 p.c.p.a. in 3 years ?

ARs 2,025

BRs 3,025

CRs 2,250

DRs 2,150

upendra ? undefined

Correct answer is: Rs 2,025

Explanation:

\(Principal = \Large \frac{SI \times 100}{Time \times Rate}\)

\(=\Large \frac{1200 \times 100}{4 \times 8}\)

=Rs.3750

\(\text{New principal }= 3×3750 = Rs.11250\)

\(\text{Therefore, S.I}. = \Large \frac{Principal \times Time \times Rate}{100}\)

\(=\Large \frac{11250 \times 3 \times 6}{100}\)
\(=Rs.2025\)

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Arun invested a sum of money at a certain rate of simple interest for a period of four years. Had he invested the same sum for a period of six years the total interest earned by him would have been fifty percent more than the earlier interest amount. What was the rate of interest per cent per annum ?

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BANK PO Exam (Allahabad Bank) 2010 click here to view all questions

Arun invested a sum of money at a certain rate of simple interest for a period of four years. Had he invested the same sum for a period of six years the total interest earned by him would have been fifty percent more than the earlier interest amount. What was the rate of interest per cent per annum ?

A4

B8

C5

DCannot be determined

upendra ? undefined

Correct answer is: Cannot be determined

Explanation:

According to the question,

\(\Large \frac{P \times R \times 6}{100}=\frac{P \times R \times 4}{100} \times \frac{150}{100}\)

This relation gives no result.

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Shamita took a loan at simple interest rate of 6 p.c.p.a in the year and it increased by 1.5 p.c.p.a every year. If she pays Rs. 8,190 as interest at the end of 3 years, what was her loan amount ?

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BANK PO Exam (Indian Bank) 2010 click here to view all questions

Shamita took a loan at simple interest rate of 6 p.c.p.a in the year and it increased by 1.5 p.c.p.a every year. If she pays Rs. 8,190 as interest at the end of 3 years, what was her loan amount ?

ARs. 36000

BRs. 35400

CRs. 36800

DNone of these

upendra ? undefined

Correct answer is: None of these

Explanation:

Let the loan amount be Rs.x,

Therefore, 8190

\(\Large \frac{x \times 6 \times 1}{100}+\frac{x \times 7.5 \times 1}{100}+\frac{x \times 9 \times 1}{100}\)

\(=>\Large \frac{22.5x}{100} = 8190 \)

\(=> x = \Large \frac{8190 \times 100}{22.5}\)= Rs.36400

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What amount a man would have received on a principal of Rs. 4,000 after two years at simple interest at the rate of 5 per cent per annum ?

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BANK PO Exam (Corporation Bank) 2009 click here to view all questions

What amount a man would have received on a principal of Rs. 4,000 after two years at simple interest at the rate of 5 per cent per annum ?

ARS 4,161

B RS 5,200

CRS 4,400

D RS 4,100

upendra ? undefined

Correct answer is: RS 4,400

Explanation:

S.I. = \(\Large \frac{Principal \times Time \times Rate}{100}\)

 

= Rs. \(\Large \left(\frac{4000 \times 2 \times 5}{100}\right)\)

Therefore, Amount received = S.I. + Principal

 

= Rs.  \(\Large \left(4000 + 400\right)\)

= Rs.4400

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The simple interest accrued on an amount of Rs. 2,500 at the end of six years is Rs. 1,875. What would be the simple interest accrued on an amount of Rs. 6,875 at the same rate and same period ? "

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BANK PO Exam (PNB Bank) 2009 click here to view all questions

The simple interest accrued on an amount of Rs. 2,500 at the end of six years is Rs. 1,875. What would be the simple interest accrued on an amount of Rs. 6,875 at the same rate and same period ?

ARs. 4,556.5

BRs. 5,025.25

CRs. 4,895.25

DNone of these

upendra ? undefined

Correct answer is: None of these

Explanation:

SI on Rs.2500 for 6 years at a certain rate = Rs.1875

=> SI on Rs. 6875 for the same period at the same rate

\(\Large \frac{1875 \times 6875}{2500}\)

=Rs.2156.25

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Vishwas borrowed a total amount of Rs. 30,000 part of it on simple interest, rate of 12 p.c.p.a. and remaining on simple interest rate of 10 p.c.p.a. If at the end of 2 years he paid in all Rs. 36,480 to settle the loan amount, what was the amount borrowed at 12 p.c.p.a.?

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BANK PO Exam (Indian Overseas Bank) 2008 click here to view all questions

Vishwas borrowed a total amount of Rs. 30,000 part of it on simple interest, rate of 12 p.c.p.a. and remaining on simple interest rate of 10 p.c.p.a. If at the end of 2 years he paid in all Rs. 36,480 to settle the loan amount, what was the amount borrowed at 12 p.c.p.a.?

A Rs. 16000

B Rs. 18000

CRs. 17500

DRs. 12000

upendra ? undefined

Correct answer is: Rs. 12000

Explanation:

Let the sum borrowed at 12% p.a. be Rs. x
and that borrowed at 10% p.a. be Rs. (30000 - x)
S.I. at the end of 2 years
= Rs. (36480 - 30000)
= Rs. 6480

\(\eqalign{ & \therefore \left( {\frac{{x \times 12 \times 2}}{{100}}} \right) + \left[ {\frac{{\left( {30000 - x} \right) \times 10 \times 2}}{{100}}} \right] = 6480 \cr & \Leftrightarrow 24x + 600000 - 20x = 648000 \cr & \Leftrightarrow 4x = 48000 \cr & \Leftrightarrow x = 12000. \cr}\)

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A certain amount earns simple Interest of Rs. 1,750/- after 7 years. Had the interest been 2% more, how much more interest would it have earned ?

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BANK PO Exam (Canara Bank) 2003 click here to view all questions

A certain amount earns simple Interest of Rs. 1,750/- after 7 years. Had the interest been 2% more, how much more interest would it have earned ?

ARs. 35/-

BRs. 350/-

CRs. 245/-

DCannot be determined

nithin ? undefined

To find out how much more interest would have been earned if the interest rate were 2% more,
we need to calculate the interest earned at the original rate and the interest earned at the increased rate.
Let's denote: - Original interest rate = \(R\) (in percentage)
- Principal amount = \(P\)
- Time period = \(T\) (in years)
- Original interest earned = \(I_1\)
- Interest earned at the increased rate = \(I_2\)
Given: - \(I_1 = Rs. 1,750\) - \(T = 7\) years We can use the formula for simple interest: \[I = \frac{P \times R \times T}{100}\] For the original interest rate: \[1750 = \frac{P \times R \times 7}{100}\] \[P \times R = \frac{1750 \times 100}{7}\] \[P \times R = 25000\] Now, if the interest rate were increased by 2%, the new rate would be \(R + 2\) (in percentage). For the increased interest rate: \[I_2 = \frac{P \times (R + 2) \times 7}{100}\] The difference in interest would be: \[\text{Difference} = I_2 - I_1\] Let's calculate \(I_2\) and the difference: \[I_2 = \frac{P \times (R + 2) \times 7}{100}\] \[= \frac{P \times (R \times 7 + 2 \times 7)}{100}\] \[= \frac{P \times (25000 + 2 \times 7)}{100}\] \[= \frac{P \times (25000 + 14)}{100}\] \[= \frac{P \times 25014}{100}\] \[= 250.14P\] Now, calculate the difference: \[\text{Difference} = I_2 - I_1\] \[= 250.14P - 1750\] We have the value of \(P\) from the earlier calculation: \[P \times R = 25000\] \[R = \frac{25000}{P}\] Substitute this value of \(R\) into the difference equation: \[\text{Difference} = 250.14P - 1750\] \[= 250.14P - 1750\] \[= 250.14 \times \frac{25000}{R} - 1750\] Now, we need to determine the value of \(R\) (original interest rate). However, it's not given, so we can't determine the exact difference. Therefore, the answer is option D: Cannot be determined.

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