A man lends Rs.1200 for 3 years. Apart he lends on 4% and rest on 6%
A man lends Rs.1200 for 3 years. Apart he lends on 4% and rest on 6% and receives Rs.192 as interest. The money he lent on 6% rate is
ARs.720
BRs.840
CRs.800
DRs.515
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Answer is :Rs.800
Explanation
If amount lend at 4% interest = x
and at 6% interest = 1200 -x
Given, \(\Big(\frac{x \times 3 \times 4}{100}\Big)+\Big(\frac{(1200-x)\times3\times6}{100}\Big)=192\)\(=>\frac{12x}{100}+\frac{21600}{100}-\frac{18x}{100 }= 192\)
\(=>\frac{12x+21600-18x}{100} = 192\)\(=> \frac{-6x+21600}{100}=192\)
\(=> 21600 -6x = 19200\)
\(=>6 x = 21600 -19200 \)
\(=> 6x = 2400\)
\(=> x = 400\)
\(\therefore \text{ the money lent on 6% rate is } = 1200 -x \)
= 1200 - 400
=800
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