12.1 19.8

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RRB TC CC Exam (Mumbai) 2006 click here to view all questions

A7/ 9

B11/18

C13/17

D11/19

Akilesh Kharvi ? Nov 6 '2016 at 11:27

Answer is : 11/18

\(=> \frac{12.1}{19.8}\)

multiply the numerator and denominator by 10

\(=>\frac{121}{198}\)

\(=> \frac{11 * 11}{11 * 18}\)

\(=\frac{11}{18}\)

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Answer is : 11/18 \(=> \frac{12.1}{19.8}\) multiply the numerator and denominator by 10 \(=>\frac{121}{198}\) \(=> \frac{11 * 11}{11 * 18}\) \(=\frac{11}{18}\) Akilesh Kharvi ? answered Nov 6 '2016 at 11:27 All Comments

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