Find the two numbers whose mean proportion is 12 and the

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RRB TC CC Exam (Mumbai) 2006 click here to view all questions

Find the two numbers whose mean proportion is 12 and the third number is 324.

A6 and 8

B4 and 36

C3 and 24

DNone of these

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Answer is : 4 and 36 Let the number be a and b $\therefore \sqrt{ab} =12$ =>$ab = 12^2=>144 ............(i)$ Again, $\frac{a}{b} = \frac{b}{324}$ $=> b^2 =324 b$ $=324 * \frac{144}{b} .......\text{From (i)}$ $=>b^3 = 324 *144$ $=> b =\sqrt[3]{324 *144} = 36$ $\therefore ab = 144$ =>$a = \frac{144}{b} =>\frac{144}{36} = 4$ $\therefore \text{a=4 and b}=36$ Akilesh Kharvi ? answered Nov 6 '2016 at 12:37 All Comments

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