If a watch runs 5 minutes fast every hour, then the angle traversed by a second hand in one minute is-

Report

Report an issue

Name

Email

Message

Submit

Cancel

RRB TC CC Exam (Bangalore) 2006 click here to view all questions

If a watch runs 5 minutes fast every hour, then the angle traversed by a second hand in one minute is-

A360

B360.5

C390

D380

Sachin Khr ? Nov 18 '2016 at 21:21

Answer is : 390
The second hand must traverse 5 * 360° = 1800° more in an hour than it should if it runs 5 minutes fast....
so,in one "normal" minute....it must traverse 1/60th of this plus its normal turn of 360°.......
\(so.... [360 + \frac{1800}{60}]° = [ 360 + 30]° = [ 390]°\)

All DiscussionsClick here to write answer

Answer is : 390 The second hand must traverse 5 * 360° = 1800° more in an hour than it should if it runs 5 minutes fast.... so,in one "normal" minute....it must traverse 1/60th of this plus its normal turn of 360°....... \(so.... [360 + \frac{1800}{60}]° = [ 360 + 30]° = [ 390]°\) Sachin Khr ? answered Nov 18 '2016 at 21:21 All Comments

Post your answers here:

Post

Post your comments here:

Message

Post

Cancel