Rs.81 is divided into 3 parts in such a way that half of the
Rs.81 is divided into 3 parts in such a way that half of the first part, one-third of the second part and one-fourth of the third part are equal. The third part is more than the first part by
Aa) 12
Bb) 18
Cc) 28
Dd) 38
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Answer is 18
let the numbers be x, y , z
So \(1\over2\) x = \(1\over3\) y = \(1\over4\)z = k
x = 2k , y = 3k , z = 4k
Also,
x+y+z = 81
2k+3k+4k = 81
9k = 81
k = 9
So numbers are
x = 2k = 18,
y =3k = 27 ,
z =4k = 36
Finally The third part is more than the first part by (z-x) =>(36-18) =>18
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