December 14, 2019 |
The radius of the outer and the inner perimeter of a circular path is 23 : 22. If
the path is 5 m wide, the diameter of the inner circle is
A110 m
B55 m
C220 m
D230 m
| Correct answer is: 220 m Explanation: Let R and r be the outer and inner radii of the circular path. Given that 2πR2πr=2322 ⟹Rr=2322 Let R = 23x and r = 22x It is given that the width of the path is 5 m wide ∴ R – r = 5 m ⇒ 23x – 22x = 5 m ⇒ x = 5 m Thus, the external diameter of the circular road = 2 × 23 × 5 m = 230 m and the internal diameter of the circular road = 2 × 22 × 5 m = 220 m Afzal ? answered Dec 23 '2019 at 10:17 All Comments
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