The radius of the outer and the inner perimeter of a circular path is 23 : 22. Ifthe path is 5 m wide, the diameter of the inner circle is

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RRB GG Exam (Bhopal) 2009 click here to view all questions

The radius of the outer and the inner perimeter of a circular path is 23 : 22. If the path is 5 m wide, the diameter of the inner circle is

A110 m

B55 m

C220 m

D230 m

Afzal ? Dec 23 '2019 at 10:17

Correct answer is: 220 m

Explanation:

Let R and r be the outer and inner radii of the circular path.

\(\text{Given that } \frac{2\pi R}{2 \pi r} = \frac{23}{22}\)

\(\implies \frac{R}{r} = \frac{23}{22}\) 

Let R = 23x and r = 22x

It is given that the width of the path is 5 m wide

∴ R – r = 5 m

⇒ 23x – 22x = 5 m

⇒ x = 5 m

Thus, the external diameter of the circular road = 2 × 23 × 5 m = 230 m and the internal diameter of the circular road = 2 × 22 × 5 m = 220 m

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Correct answer is: 220 m Explanation: Let R and r be the outer and inner radii of the circular path. \(\text{Given that } \frac{2\pi R}{2 \pi r} = \frac{23}{22}\) \(\implies \frac{R}{r} = \frac{23}{22}\)  Let R = 23x and r = 22x It is given that the width of the path is 5 m wide ∴ R – r = 5 m ⇒ 23x – 22x = 5 m ⇒ x = 5 m Thus, the external diameter of the circular road = 2 × 23 × 5 m = 230 m and the internal diameter of the circular road = 2 × 22 × 5 m = 220 m Afzal ? answered Dec 23 '2019 at 10:17 All Comments

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