Seema’s present age is four times her son’s present age and four-seventh of her father’s present age. The average of the present ages of all three of them is 32 years. What is the difference between the Seema’s son’spresent age and Seema’s father’s presentage ?
Seema’s present age is four times her son’s present age and four-seventh of her father’s present age. The average of the present ages of all three of them is 32 years. What is the difference between the Seema’s son’spresent age and Seema’s father’s presentage ?
A44 years
B48 years
C46 years
DCannot be determined
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Answer is 48 years
Explanation:
Let Seema’s son’s present age = x years
\(\therefore\) Seema’s present age = 4x years
Seema’s husband’s present age
\(= 4x ×\frac{7}{4} = 7x \text { years}\)
\(\therefore x + 4x + 7x = 32 × 3\)
\(=>12x = 96\) \(=>x = \frac{96}{12}= 8\)
\(\therefore \) Required difference
= 7x - x = 6x
= 6 × 8 = 48 years
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