To m litres of a m% solution of acid. x litres of water is muted to yield (m - 10)% solution of acid. If m > 25. then x equals

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INSURANCE EXAMS (New India Assurance) 2009 click here to view all questions

To m litres of a m% solution of acid. x litres of water is muted to yield (m - 10)% solution of acid. If m > 25. then x equals

A$\frac{10m}{m-10}$

B$\frac{5m}{m-10}$

C$\frac{2m}{m-10}$

D$\frac{m}{m-10}$

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Correct answer is: $\frac{10m}{m-10}$ Explanation: Tricky approach $\text{ Acid = }\frac{m}{100} \times m = \frac{m^{2}}{100}$ $\text{New percentage =} \frac{m^{2} \times 100}{ \left(m+x\right) \times 100 }$ $\implies \frac{m^{2}}{m+x}=m-10$ $\implies m^{2} - 10m + mx - 10x = m^{2}$ $\implies x \left(m-10\right)=10m$ $\implies x = \frac{10m}{m-10}$ Nithin ? answered undefined All Comments

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