The marked price of a article is Rs. 4000. If the shopkeeper sold the article at 10% discount but still got a profit of 20%, find the cost price of the article.

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RRB NTPC Exam 19 Jan 2021 click here to view all questions

The marked price of a article is Rs. 4000. If the shopkeeper sold the article at 10% discount but still got a profit of 20%, find the cost price of the article.

ARs. 3200

BRs. 2880

CRs. 3000

DRs. 3300

Akhilesh ? Apr 17 '25 at 21:47

Correct answer: Rs. 3000

Explanation:

Let the cost price (CP) be \( x \)
The marked price (MP) is Rs. 4000.
The discount is 10%, so the selling price (SP) is 90% of MP:

\(SP = 4000 \times (1 - 0.10) = 4000 \times 0.90 = 3600\)

The profit is 20%, so: \[ SP = CP \times (1 + 0.20) \]

Substituting SP: \[ 3600 = x \times 1.20 \] Solving for \( x \):

\[ x = \frac{3600}{1.20} = 3000 \]

Final Answer: \(\boxed{3000}\)

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Correct answer: Rs. 3000 Explanation: Let the cost price (CP) be \( x \) The marked price (MP) is Rs. 4000. The discount is 10%, so the selling price (SP) is 90% of MP: \(SP = 4000 \times (1 - 0.10) = 4000 \times 0.90 = 3600\) The profit is 20%, so: \[ SP = CP \times (1 + 0.20) \] Substituting SP: \[ 3600 = x \times 1.20 \] Solving for \( x \): \[ x = \frac{3600}{1.20} = 3000 \] Final Answer: \(\boxed{3000}\) Akhilesh ? answered Apr 17 '25 at 21:47

Correct answer: Rs. 3000 Explanation: Let the cost price (CP) be \( x \) The marked price (MP) is Rs. 4000. The discount is 10%, so the selling price (SP) is 90% of MP: \(SP = 4000 \times (1 - 0.10) = 4000 \times 0.90 = 3600\) The profit is 20%, so: \[ SP = CP \times (1 + 0.20) \] Substituting SP: \[ 3600 = x \times 1.20 \] Solving for \( x \): \[ x = \frac{3600}{1.20} = 3000 \] Final Answer: \(\boxed{3000}\) Akhilesh ? answered Apr 17 '25 at 21:47

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