12.1 19.8

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RRB TC CC Exam (Mumbai) 2006 click here to view all questions

A7/ 9

B11/18

C13/17

D11/19

Akilesh Kharvi ? Nov 6 '2016 at 11:27

Answer is : 11/18

\(=> \frac{12.1}{19.8}\)

multiply the numerator and denominator by 10

\(=>\frac{121}{198}\)

\(=> \frac{11 * 11}{11 * 18}\)

\(=\frac{11}{18}\)

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Rs.81 is divided into 3 parts in such a way that half of the

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RRB TC CC Exam (Patna) 2006 click here to view all questions

Rs.81 is divided into 3 parts in such a way that half of the first part, one-third of the second part and one-fourth of the third part are equal. The third part is more than the first part by

Aa) 12

Bb) 18

Cc) 28

Dd) 38

Akilesh Kharvi ? Nov 5 '2016 at 13:43

Answer is 18
let the numbers be x, y , z
So \(1\over2\) x = \(1\over3\) y = \(1\over4\)z = k
x = 2k , y = 3k , z = 4k
Also,
x+y+z = 81
2k+3k+4k = 81
9k = 81
k = 9
So numbers are 
x = 2k = 18,
y =3k = 27 ,
z =4k = 36
Finally The third part is more than the first part by (z-x) =>(36-18) =>18

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A two digit number is five times the sum of its digits. If 9

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RRB TC CC Exam (Bangalore) 2007 click here to view all questions

A two digit number is five times the sum of its digits. If 9 is added to the number, the digits interchange. Find the sum of the digits.

A11

B7

C6

D9

quiaz ? Dec 20 '2018 at 14:16

Let a and b the digits we can write the number as "ab" but the number is \(10 \times a+b\)
(for example if a=3 and b=2 the number would be 32 and \(32 =10 \times 3+2\)) 

a two digit number is 5 times the sum of its digit then \(10 \times a+b=5(a+b)\)
when 9 is added to the number the result is the original number with its reversed \(10 \times a+b+9=10 \times b+a \)
then we have the following equations: 
\(10 \times a+b=5(a+b)\)
\(10 \times a+b+9=10 \times b+a \)
then 
\(10a+b=5a+5b\)
\(10a+b+9=10b+a \)
then 
\(5a-4b=0\)

 
\(9a-9b=-9 \)
then 
\(5a-4b=0\)
\(a-b=-1\)
then using 2nd eq a=b-1 
using 1st eq \(5(b-1)-4b=0 \)
then \(5b-5-4b=0\)
then b=5 and a=5-1=4 
the sum of digits is 9.

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(45 + 46 + 47 + ....... + 113 + 114 + 115) is equal to

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RRB ASM Exam (Ajmer) 2007 click here to view all questions

(45 + 46 + 47 + ....... + 113 + 114 + 115) is equal to-

A5600

B5656

C5680

D4000

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A rationalising factor of

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RRB ASM Exam (Ajmer) 2007 click here to view all questions

A rationalising factor of is -

A

B

C

D

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