After measuring 120 m of a rope, it was discovered that the
After measuring 120 m of a rope, it was discovered that the measuring metre rod was there centimetres longer. The true length of the rope measured is-
After measuring 120 m of a rope, it was discovered that the measuring metre rod was there centimetres longer. The true length of the rope measured is-
Nithin K ? Nov 20 '2016 at 19:30
Answer is : 123 m 60 cm
Explanation:
Geven Data,
The length of the rod = 3 cm
To measure 120 m , Rod is apply by 120 times .
Therefore, total length that is measure by longer part = 120 x 3
= 360 cm = 3.60 m (∵ 100cm = 1m)
Then, the actual length of rope = 120m + 3.6m
= 123 m 60 cm
Hence, the answer is 123 m 60 cm.
A 2-digit number is 3 times the sum of its digits. If 45 is added to the number, its digits are interchanged. The sum of digits of the number is-
Nithin K ? Nov 20 '2016 at 19:27
Answer is : 9
Explanation:
A 2-digit number is 3 times the sum of its digits.
10y + x = 3(x + y)
10y + x = 3x + 3y
2x - 7y = 0 .........................(i)If 45 is added to the number, its digits are interchanged.
10y + x + 45 = 10x + y
9x - 9y = 45 .......................(ii)On Solving equation (i) and (ii)
x= 7
y= 2
number = 27
sum of the digits =(x+y)=(7+2)= 9
64329 is divided by a certain number. While dividing the numbers 175, 114 and 213 appear as three successive remainders. The divisor is-
Nithin K ? Nov 20 '2016 at 19:24
Answer is : 234
Explanation:
There are 3 remainders and they are 3 digit numbers so it is evident that the divisor is also 3 digit number.
We have three remainders, means the number comprising of the first digits i.e. 643 was divided first and we got 175 as the remainder.
Now according to DIVIDEND = DIVISOR x QUOTIENT + REMAINDER
=> DIVISOR x QUOTIENT = DIVIDEND – REMAINDER
=> DIVISOR x QUOTIENT = 643 – 175 = 468Now Take The Options One by one
468 is not divisible by 184
468 is not divisible by 224
468 is not divisible by 296
We see that 468 is divisible by 234 only among all the answer options; so 234 is the divisor we need.
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There are sets of English, Mathematics and Science books containing 336, 240, 96 books respectively have to be stacked in such a way that all the books are stored subject-wise and the height of each stack is the same. Total number of stacks will be-
Nithin K ? Nov 20 '2016 at 17:34
Answer is : 14
First the number of books in each stack is HCF[336, 240,96] = 48
Total number of stacks = \(\frac{336}{48} + \frac{240}{48} +\frac{96}{48} = 14.\)