the value of

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A2

B3.8

C0.6

D4.2

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Rs.750 are divided among A, B and C in such a manner that A

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Rs.750 are divided among A, B and C in such a manner that A : B = 5 : 2 and B : C = 7 : 13. What is A's share?

ARs.350

BRs.260

CRs.140

DRs.250

Nithin K ? Dec 4 '2016 at 18:40

Answer : Rs.350

Explanation:

\(A : B = 5 : 2 = \frac{5}{2} : 1, \)

\(B : C = 7 : 13 = 1 : \frac{13}{7} \)
\(A : B : C = \frac{5}{2} : 1 : \frac{13}{7} = 35 : 14 : 26 \)
 \(\therefore \text{ A's part }= 750 \times \frac{35}{75} = \text{Rs } 350\)

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Some articles were bought at 6 for Rs.5, and sold at 5 for

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Some articles were bought at 6 for Rs.5, and sold at 5 for Rs.6. Gain percentage is

A5%

B6%

C30%

D44%

Nithin K ? Dec 4 '2016 at 14:46

Answer : 44%

Explanation :

Suppose, number of articles bought = L.C.M. of 6 and 5 = 30.

C.P. of 30 articles = \(\frac{5}{6} \times 30 = 25. \)

S.P. of 30 articles = \(\frac{6}{5} \times 30 = 36 \)

\(Gain\% = \frac{11}{25} \times 100 \% = 44\%.\)

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The percentage increase in the area of a rectangle, if each

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The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is

A40%

B42%

C44%

D46%

Nithin K ? Dec 4 '2016 at 14:38

Answer :  44%

Explanation:

Let original length = x metres and original breadth = y metres.
Original area = \(\text{xy }m^2\)

Increased length  \(= \frac{120}{100}x\)  and Increased breadth \(= \frac{120}{100}y\)

New area \(=\frac{120}{100}x \times \frac{120}{100}y\)

\(= \frac{36}{25}\text{xy } m^2\)

The difference between the Original area  and New area  is:

\(=\frac{36}{25}xy -xy\)  

\(=\frac{11}{25} xy\)

Increase %  \(= \frac{\frac{11}{25}xy}{xy} \times 100\)  

= 44%

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A truck covers a distance of 550 m in 1 min whereas a bus

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A truck covers a distance of 550 m in 1 min whereas a bus covers a distance of 33 km/s in 45 min. The ratio of their speeds is

A4:3

B3:5

C3:4

D50:3

Nithin K ? Dec 4 '2016 at 14:22

Answer: 3:4

Explanation:

Ratio of speeds = \(\Big(\frac{550}{60} \times \frac{18}{5}\Big): \Big(\frac{33}{45}\times60\Big)\)

= 33 : 44

= 3 : 4.

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A man can do a piece of work in 5 days, but with the help of

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A man can do a piece of work in 5 days, but with the help of his son, he can do it in 3 days. In what time can the son do it alone?

A

B

C

D

Nithin K ? Dec 4 '2016 at 14:12

Answer:  \(5\frac{1}{2} days\)

Explanation:

Son's one day work = \(\Big( \frac{1}{3} - \frac{1}{5} \Big)\)

\(=\Big(\frac{5-3}{15}\Big)\)

\(=\frac{2}{15}\)

So son will do whole work in \(\frac{15}{2}\) days
which is = \(5\frac{1}{2} days\)

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The average weight of A, B, C is 45 kg if the average weight

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The average weight of A, B, C is 45 kg if the average weight of A and B be 40 kg and that of B and C is 43 kg, then the weight of B is

A17 kg

B20 kg

C26 kg

D31 kg

Nithin K ? Dec 4 '2016 at 13:47

Answer: 31 kg

Explanation:

Let A, B, C represent their respective weights. Then, we have:

A + B + C = (45 x 3) = 135 .... (i)

A + B = (40 x 2) = 80 .... (ii)

B + C = (43 x 2) = 86 ....(iii)

Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)

Subtracting (i) from (iv), we get : B = 31.

B's weight = 31 kg.

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