If 378 coins consists of rupees, 50 paise and 25 paise coins whose values are inthe ratio of 13 : 11 : 7. The number of 50 paise coins will be

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If 378 coins consists of rupees, 50 paise and 25 paise coins whose values are in the ratio of 13 : 11 : 7. The number of 50 paise coins will be

A132

B128

C136

D133

prajwal ? Dec 20 '2019 at 15:41

Correct answer is: 132

Explanation:
Total coins = 378

Ratio of values -> 13 : 11 : 7

In Rs. 1, no. of rs. 1 coins = 1

In Rs. 1, no. of 50 P coins = 2

in Rs. 1, no. of 25 P coins = 4

Ratio of Rs. 1, 50 P, 25 P coins = \(\Large 13 \times 1 : 11 \times 2 : 7 \times 4\)

= 13 : 22 : 28

No. of 50 P coins = \(\Large \frac{22}{13 + 22 + 28} \times 378 = 132\)

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In an alloy, the ratio of Copper and Zinc is 5 : 2. If 1.250 Kg of Zinc is mixedin 17 Kg 500 g of alloy, then the ratio of Copper and Zinc will be

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In an alloy, the ratio of Copper and Zinc is 5 : 2. If 1.250 Kg of Zinc is mixed in 17 Kg 500 g of alloy, then the ratio of Copper and Zinc will be

A2 : 1

B2 : 3

C3 : 2

D1 : 2

prakash ? Dec 20 '2019 at 16:23

 

Correct answer is: 2 : 1

Explanation:

Quantity of copper in 17.5kg of alloy

\(=\Big(17.5 \times \frac{5}{7}\Big) \text{ kg}\)

 

= 12.5kg.

\(=\Big(17.5 \times \frac{2}{7}\Big) \text{ kg}\)

= 5kg

 

∴ Required ratio=12.5:(5+1.25)

= 12.5:6.25

= 2:1

 

 

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Sonu's father is five times older than Sonu. After 8 yr, his age will be three timesthe Sonu's age that time. Their present ages are

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Sonu's father is five times older than Sonu. After 8 yr, his age will be three times the Sonu's age that time. Their present ages are

A30 yr, 6 yr

B35 yr, 7 yr

C40 yr, 8 yr

D45 yr, 9 yr

prashanth ? Dec 20 '2019 at 17:1

Correct answer is: 40 yr, 8 yr

Explanation:

Let the age of Sonu be x yr

∴ Age of Sonu’s father = 5x yr

5x + 8 = 3(x + 8)

5x + 8 = 3x + 24

2x = 16

x = 8

∴ Age of Sonu is 8 yr and age of his father is 40 yr.

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The radius of the outer and the inner perimeter of a circular path is 23 : 22. Ifthe path is 5 m wide, the diameter of the inner circle is

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The radius of the outer and the inner perimeter of a circular path is 23 : 22. If the path is 5 m wide, the diameter of the inner circle is

A110 m

B55 m

C220 m

D230 m

Afzal ? Dec 23 '2019 at 10:17

Correct answer is: 220 m

Explanation:

Let R and r be the outer and inner radii of the circular path.

\(\text{Given that } \frac{2\pi R}{2 \pi r} = \frac{23}{22}\)

\(\implies \frac{R}{r} = \frac{23}{22}\) 

Let R = 23x and r = 22x

It is given that the width of the path is 5 m wide

∴ R – r = 5 m

⇒ 23x – 22x = 5 m

⇒ x = 5 m

Thus, the external diameter of the circular road = 2 × 23 × 5 m = 230 m and the internal diameter of the circular road = 2 × 22 × 5 m = 220 m

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If the volume of two cubes are in the ratio of 27 : 64, then the ratio of their total surface area is

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If the volume of two cubes are in the ratio of 27 : 64, then the ratio of their total surface area is

A27 : 64

B3 : 4

C9 : 16

D3 : 8

prasad ? Dec 20 '2019 at 17:9

Correct answer is:  9 : 16

Explanation:

\(\Large \frac{(a_{1})^{3}}{(a_{2})^{3}}=\frac{27}{64}\)

\(\Large \frac{a_{1}}{a_{2}}=\frac{3}{4}\)

Ratio of their total surface area

\(\Large =\frac{6a_{1}^{2}}{6a_{2}^{2}}= \left(\frac{a_{1}}{a_{2}}\right)^{2}\)

\(\Large = \left(\frac{3}{4}\right)^{2}=\frac{9}{16}=9:16\)

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A builder borrows Rs.2550 to be paid back with compound interest at the rate of4% per annum by the end of 2 yr in two equal yearly installments. How muchwill each installment be?

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A builder borrows Rs.2550 to be paid back with compound interest at the rate of 4% per annum by the end of 2 yr in two equal yearly installments. How much will each installment be?

ARs.1352

BRs.1377

CRs.1275

DRs.1283

prakash ? Dec 23 '2019 at 10:32

Correct answer is: Rs.1352

Explanation:

Amount = Rs 2550

Rate = 4% per annum

Time = 2 years

Applying the formula

\(P= \frac{X}{\Big(1+\frac{r}{100}\Big)^n}+ …………………….\frac{X}{\Big(1+\frac{r}{100}\Big)}\)

Here we have two equal installments, so

\(P= \frac{X}{\Big(1+\frac{r}{100}\Big)^2} + \frac{X}{\Big(1+\frac{r}{100}\Big)}\)

\(\implies 2550= \frac{X}{\Big(1+\frac{4}{100}\Big)^2} + \frac{X}{\Big(1+\frac{4}{100}\Big)}\)

\(\implies X = \text{ Rs 1352}\)

 

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Rs.500 was invested at 12% per annum simple interest and a certain sum ofmoney at 10% per annum simple interest. If the sum of the interests on both thesums after 4 yr is Rs.480, the latter sum of money is

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Rs.500 was invested at 12% per annum simple interest and a certain sum of money at 10% per annum simple interest. If the sum of the interests on both the sums after 4 yr is Rs.480, the latter sum of money is

ARs.450

BRs.750

CRs.600

DRs.550

prashanth ? Dec 23 '2019 at 10:38

Correct answer is: Rs.600

Explanation:
Simple interest gained from Rs. 500 = \(\frac{500 \times 12 \times 4}{100}\) = Rs. 240
Let the other principal be x.
S.I. gained = Rs. (480 – 240) = Rs. 240

\(\therefore \frac{x \times 10 \times 4}{100} =240\)

\(\therefore x = \frac{240 \times 100}{40} = 600\)

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