A man can do a piece of work in 5 days, but with the help of his son, he can doit in 3 days. In what time can the son do it alone?

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A man can do a piece of work in 5 days, but with the help of his son, he can do it in 3 days. In what time can the son do it alone?

A7 days

B8 days

C7.5 days

D6.5 days

raveesh ? Dec 23 '2019 at 9:17

Correct Answer is : 7.5 days

Explanation:

In this type of question, where we have one person work and together work done. Then we can easily get the other person work just by subtracting them. As,

Son's one day work

 \(\begin{aligned} \left(\frac{1}{3}-\frac{1}{5} \right) \\ =\left(\frac{5-3}{15} \right) \\ = \frac{2}{15} \end{aligned}\)

So son will do whole work in \(\frac{15}{2}\)  days
which is =

\(\begin{aligned} 7\frac{1}{2}days \end{aligned}\)

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A and B can complete a work in 15 days and 10 days respectively. They starteddoing the work together, but after 2 days B had to leave and A alone completedthe remaining work. The whole work was completed in

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A and B can complete a work in 15 days and 10 days respectively. They started doing the work together, but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in

A10 days

B8 days

C12 days

D15 days

prakash ? Dec 18 '2019 at 9:8

Correct answer is: 12 days

Explanation:

The work completed by both in 2 days is

\(2\big(\frac{ 1}{15} + \frac{1}{10}\big) = \frac{1}{3}.\)

Work done by A alone is \(\frac{2}{3}\)

For full work A needs 15 days

For 2/3 work the days needed is \( (\frac{2}{3})\times15\) = 10 days.

The work was completed in 10 +2 = 12 days.

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5 persons can prepare an admission list in 8 days working 7 hours a day. If 2persons join them so as to complete the work in 4 days, they need to work perFor

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5 persons can prepare an admission list in 8 days working 7 hours a day. If 2 persons join them so as to complete the work in 4 days, they need to work per For

A10 hours

B9 hours

C12 hours

D8 hours

prashanth ? Dec 18 '2019 at 9:30

Correct answer is: 10 hours

Explanation:

\(\Large \frac{5 \text{ person} \times 8 \text{ days} \times 7hr}{1}= \frac{\left(5+2 \text{ person}\right) \times 4 \text{ days} \times Hperday}{1}\)

=10 hours

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If 378 coins consists of rupees, 50 paise and 25 paise coins whose values are inthe ratio of 13 : 11 : 7. The number of 50 paise coins will be

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If 378 coins consists of rupees, 50 paise and 25 paise coins whose values are in the ratio of 13 : 11 : 7. The number of 50 paise coins will be

A132

B128

C136

D133

prajwal ? Dec 20 '2019 at 15:41

Correct answer is: 132

Explanation:
Total coins = 378

Ratio of values -> 13 : 11 : 7

In Rs. 1, no. of rs. 1 coins = 1

In Rs. 1, no. of 50 P coins = 2

in Rs. 1, no. of 25 P coins = 4

Ratio of Rs. 1, 50 P, 25 P coins = \(\Large 13 \times 1 : 11 \times 2 : 7 \times 4\)

= 13 : 22 : 28

No. of 50 P coins = \(\Large \frac{22}{13 + 22 + 28} \times 378 = 132\)

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In an alloy, the ratio of Copper and Zinc is 5 : 2. If 1.250 Kg of Zinc is mixedin 17 Kg 500 g of alloy, then the ratio of Copper and Zinc will be

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In an alloy, the ratio of Copper and Zinc is 5 : 2. If 1.250 Kg of Zinc is mixed in 17 Kg 500 g of alloy, then the ratio of Copper and Zinc will be

A2 : 1

B2 : 3

C3 : 2

D1 : 2

prakash ? Dec 20 '2019 at 16:23

 

Correct answer is: 2 : 1

Explanation:

Quantity of copper in 17.5kg of alloy

\(=\Big(17.5 \times \frac{5}{7}\Big) \text{ kg}\)

 

= 12.5kg.

\(=\Big(17.5 \times \frac{2}{7}\Big) \text{ kg}\)

= 5kg

 

∴ Required ratio=12.5:(5+1.25)

= 12.5:6.25

= 2:1

 

 

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Sonu's father is five times older than Sonu. After 8 yr, his age will be three timesthe Sonu's age that time. Their present ages are

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Sonu's father is five times older than Sonu. After 8 yr, his age will be three times the Sonu's age that time. Their present ages are

A30 yr, 6 yr

B35 yr, 7 yr

C40 yr, 8 yr

D45 yr, 9 yr

prashanth ? Dec 20 '2019 at 17:1

Correct answer is: 40 yr, 8 yr

Explanation:

Let the age of Sonu be x yr

∴ Age of Sonu’s father = 5x yr

5x + 8 = 3(x + 8)

5x + 8 = 3x + 24

2x = 16

x = 8

∴ Age of Sonu is 8 yr and age of his father is 40 yr.

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The radius of the outer and the inner perimeter of a circular path is 23 : 22. Ifthe path is 5 m wide, the diameter of the inner circle is

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The radius of the outer and the inner perimeter of a circular path is 23 : 22. If the path is 5 m wide, the diameter of the inner circle is

A110 m

B55 m

C220 m

D230 m

Afzal ? Dec 23 '2019 at 10:17

Correct answer is: 220 m

Explanation:

Let R and r be the outer and inner radii of the circular path.

\(\text{Given that } \frac{2\pi R}{2 \pi r} = \frac{23}{22}\)

\(\implies \frac{R}{r} = \frac{23}{22}\) 

Let R = 23x and r = 22x

It is given that the width of the path is 5 m wide

∴ R – r = 5 m

⇒ 23x – 22x = 5 m

⇒ x = 5 m

Thus, the external diameter of the circular road = 2 × 23 × 5 m = 230 m and the internal diameter of the circular road = 2 × 22 × 5 m = 220 m

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