The average of the 9 consecutive positive integers is 63. The product of the largest and smallest integers is
The average of the 9 consecutive positive integers is 63. The product of the largest and smallest integers is
The average of the 9 consecutive positive integers is 63. The product of the largest and smallest integers is
undefined ? Jan 29 '2018 at 21:48
if average of 9 consecutive positive integers is 63 then its middle number is 63, so number series becomes
(63-4), (63-3), (63-2), (63-1), 63, (63+1), (63+2), (63+3), (63+4)59, 60, 61, 62, 63, 64, 65, 66, 67
Fifth number = 63
Smallest number = 59
Largest number = 67
Required product = 59 × 67 = 3953
The average height of 27 persons was recorded as 162 cm. If the height of Shreyas was deleted from the observation, the aver-age height reduced by 1 cm. What was Shreyas’ height ?
Nithin K ? May 26 '2017 at 20:33
Answer is 188 cm.
Explanation:
Height of Shreyas
= 162 × 27 - 161 × 26
= 188 cm
The average of four consecutive even numbers P, Q, R and S respectively (in increasing order) is 51. What is the product of P and R ?
Nithin K ? May 26 '2017 at 20:4
Answer is : 2496
Explanation:
x + x + 2 + x + 4 + x + 6= 4 × 51
4x + 12 = 204
4x = 204- 12
4x = 192
x = 48 =P
R = 48 + 4 = 52
P × R = 48 × 52
= 2496
Farah was married 8 years ago. Today her age is 1 (2/7) times to that at the time of marriage. At present her daughter's age is 1/6 th of her age.What was her daughter's age 3 years ago ?
Nithin K ? May 26 '2017 at 19:12
Answer is 3 years
Explanation
Let Farah’s age 8 years ago be x years
Farah’s present age = (x + 8) years
\(x + 8 = \frac{9x}{7}\)
7x + 56 = 9x
2x = 56
x = 28
Farah’s present age= 28 + 8 = 36 years
Her daughter’s age 3 years ago
\(= 36 \times \frac{1}{6} - 3 = 3 \text{ years }\)
Amit's present age is three times pratibha's present age and nine thirteenth of his father's present age. The sum of the present age of all of them is 150 years. What is the difference between pratibha's present age and Amit's father's present age ?
Nithin K ? May 24 '2017 at 21:50
Answer is 60 years
Explanation:
Pratibha’s present age = x years
Amit’s present age = 3x years
Father’s present age
\(= \frac{3x \times 13}{9} = \frac{13x}{3} years\)
\(\therefore x + 3x + \frac{13x}{3}= 150\)
=> 3x + 9x + 13x = 150 × 3
=> 25x = 150 × 3
=> \(= \frac{150\times3}{25}= 18\)
\(\text{Required difference }\)
\(=\frac{ 13x}{3}- x = \frac{10x}{3}\)
\(= \frac{10}{3}× 18 = 60 \text { years}\)
The average marks in English subject of a class of 24 students is 56. If the marks of three students were misread as 44, 45 and61 of the actual marks 48, 59 and 67 respectively, then what would be the correct average ?
Nithin K ? May 24 '2017 at 20:51
Anwer is : 57
Explanation:
Difference = 48 + 59 + 67 - 44 - 45 - 61= 24
Correct average = \(56+ \frac{ 24}{24} = 57\)
The sum of 8 consecutive odd numbers is 656. Also average of four consecutive even numbers is 87. What is the sum of the smallest odd number and second largest even number ?
Nithin K ? May 23 '2017 at 19:16
Answer is : 163
Explanation:
x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10+ x + 12 + x + 14 = 656
8x + 56 = 656
8x = 600
\( x = \frac{600}{8} = 75\)
and,
x + x + 2 + x + 4 + x + 6 = 87 × 4
\(=>4x + 12 = 348\)
\(=> 4x = 336\)
\(\implies x = \frac{336}{4} = 84\)
Required sum = 75 + (84 + 4) = 163