The present age of Romila is one fourth of that of her father. After 6 years the father’s age will be twice the age of Kapil. If Kapil celebrated fifth birth day 8 years ago, What is Romils’s present age ?

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The present age of Romila is one fourth of that of her father. After 6 years the father’s age will be twice the age of Kapil. If Kapil celebrated fifth birth day 8 years ago, What is Romils’s present age ?

A7 years

B7.5 years

C8 years

D8.5 years

Akilesh Kharvi ? May 27 '2017 at 12:23

Answer is : 7.5 years

Explanation:

Kapil’s present age = 12 years

After 6 years, Kapil’s age = 18 years

Father’s present age = 18 × 2 - 6= 30 years

Romlla’s present age = \(\frac{1}{4}× 30 = 7.5 years\)

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The average of the 9 consecutive positive integers is 63. The product of the largest and smallest integers is

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The average of the 9 consecutive positive integers is 63. The product of the largest and smallest integers is

A3935

B3953

C3853

D3835

undefined ? Jan 29 '2018 at 21:48

if average of 9 consecutive positive integers is 63 then its middle number is 63, so number series becomes
(63-4), (63-3), (63-2), (63-1), 63, (63+1), (63+2), (63+3), (63+4)

59, 60, 61, 62, 63, 64, 65, 66, 67

Fifth number = 63

Smallest number = 59

Largest number = 67

Required product = 59 × 67 = 3953

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The average height of 27 persons was recorded as 162 cm. If the height of Shreyas was deleted from the observation, the aver-age height reduced by 1 cm. What was Shreyas’ height ?

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The average height of 27 persons was recorded as 162 cm. If the height of Shreyas was deleted from the observation, the aver-age height reduced by 1 cm. What was Shreyas’ height ?

A188 cm.

B226 cm.

C179 cm.

D186 cm.

Nithin K ? May 26 '2017 at 20:33

Answer is 188 cm.

Explanation:

Height of Shreyas

= 162 × 27 -  161 × 26

= 188 cm

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The average of four consecutive even numbers P, Q, R and S respectively (in increasing order) is 51. What is the product of P and R ?

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The average of four consecutive even numbers P, Q, R and S respectively (in increasing order) is 51. What is the product of P and R ?

A2592

B2400

C2496

D2808

Nithin K ? May 26 '2017 at 20:4

Answer is : 2496

Explanation:

 x + x + 2 + x + 4 + x + 6= 4 × 51

4x + 12 = 204

4x = 204- 12

4x = 192

x = 48 =P

R = 48 + 4 = 52

P × R = 48 × 52

= 2496

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Farah was married 8 years ago. Today her age is 1 (2/7) times to that at the time of marriage. At present her daughter's age is 1/6 th of her age.What was her daughter's age 3 years ago ?

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Farah was married 8 years ago. Today her age is 1 (2/7) times to that at the time of marriage. At present her daughter's age is 1/6 th of her age.What was her daughter's age 3 years ago ?

A6 years

B7 years

C3 years

DCannot be determined

Nithin K ? May 26 '2017 at 19:12

Answer is 3 years

Explanation

Let Farah’s age 8 years ago be x years

Farah’s present age = (x + 8) years

\(x + 8 = \frac{9x}{7}\)

7x + 56 = 9x

2x = 56

x = 28

Farah’s present age= 28 + 8 = 36 years

Her daughter’s age 3 years ago

\(= 36 \times \frac{1}{6} - 3 = 3 \text{ years }\)

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Amit's present age is three times pratibha's present age and nine thirteenth of his father's present age. The sum of the present age of all of them is 150 years. What is the difference between pratibha's present age and Amit's father's present age ?

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Amit's present age is three times pratibha's present age and nine thirteenth of his father's present age. The sum of the present age of all of them is 150 years. What is the difference between pratibha's present age and Amit's father's present age ?

A56 years

B64 years

C60 years

DCannot be determined

Nithin K ? May 24 '2017 at 21:50

Answer is  60 years

Explanation:

Pratibha’s present age = x years

Amit’s present age = 3x years

Father’s present age

\(= \frac{3x \times 13}{9} = \frac{13x}{3} years\)

\(\therefore x + 3x + \frac{13x}{3}= 150\)

=> 3x + 9x + 13x = 150 × 3

=> 25x = 150 × 3

=> \(= \frac{150\times3}{25}= 18\)

\(\text{Required difference }\)

\(=\frac{ 13x}{3}- x = \frac{10x}{3}\)

\(= \frac{10}{3}× 18 = 60 \text { years}\)

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The average marks in English subject of a class of 24 students is 56. If the marks of three students were misread as 44, 45 and61 of the actual marks 48, 59 and 67 respectively, then what would be the correct average ?

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The average marks in English subject of a class of 24 students is 56. If the marks of three students were misread as 44, 45 and61 of the actual marks 48, 59 and 67 respectively, then what would be the correct average ?

A56

B55

C57.5

D57

Nithin K ? May 24 '2017 at 20:51

Anwer is : 57

Explanation:

Difference = 48 + 59 + 67 - 44 - 45 - 61= 24

Correct average = \(56+ \frac{ 24}{24} = 57\)

 

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