What amount a man would have received on a principal of Rs. 4,000 after two years at simple interest at the rate of 5 per cent per annum ?

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BANK PO Exam (Corporation Bank) 2009 click here to view all questions

What amount a man would have received on a principal of Rs. 4,000 after two years at simple interest at the rate of 5 per cent per annum ?

ARS 4,161

B RS 5,200

CRS 4,400

D RS 4,100

upendra ? undefined

Correct answer is: RS 4,400

Explanation:

S.I. = \(\Large \frac{Principal \times Time \times Rate}{100}\)

 

= Rs. \(\Large \left(\frac{4000 \times 2 \times 5}{100}\right)\)

Therefore, Amount received = S.I. + Principal

 

= Rs.  \(\Large \left(4000 + 400\right)\)

= Rs.4400

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The simple interest accrued on an amount of Rs. 2,500 at the end of six years is Rs. 1,875. What would be the simple interest accrued on an amount of Rs. 6,875 at the same rate and same period ? "

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BANK PO Exam (PNB Bank) 2009 click here to view all questions

The simple interest accrued on an amount of Rs. 2,500 at the end of six years is Rs. 1,875. What would be the simple interest accrued on an amount of Rs. 6,875 at the same rate and same period ?

ARs. 4,556.5

BRs. 5,025.25

CRs. 4,895.25

DNone of these

upendra ? undefined

Correct answer is: None of these

Explanation:

SI on Rs.2500 for 6 years at a certain rate = Rs.1875

=> SI on Rs. 6875 for the same period at the same rate

\(\Large \frac{1875 \times 6875}{2500}\)

=Rs.2156.25

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Vishwas borrowed a total amount of Rs. 30,000 part of it on simple interest, rate of 12 p.c.p.a. and remaining on simple interest rate of 10 p.c.p.a. If at the end of 2 years he paid in all Rs. 36,480 to settle the loan amount, what was the amount borrowed at 12 p.c.p.a.?

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BANK PO Exam (Indian Overseas Bank) 2008 click here to view all questions

Vishwas borrowed a total amount of Rs. 30,000 part of it on simple interest, rate of 12 p.c.p.a. and remaining on simple interest rate of 10 p.c.p.a. If at the end of 2 years he paid in all Rs. 36,480 to settle the loan amount, what was the amount borrowed at 12 p.c.p.a.?

A Rs. 16000

B Rs. 18000

CRs. 17500

DRs. 12000

upendra ? undefined

Correct answer is: Rs. 12000

Explanation:

Let the sum borrowed at 12% p.a. be Rs. x
and that borrowed at 10% p.a. be Rs. (30000 - x)
S.I. at the end of 2 years
= Rs. (36480 - 30000)
= Rs. 6480

\(\eqalign{ & \therefore \left( {\frac{{x \times 12 \times 2}}{{100}}} \right) + \left[ {\frac{{\left( {30000 - x} \right) \times 10 \times 2}}{{100}}} \right] = 6480 \cr & \Leftrightarrow 24x + 600000 - 20x = 648000 \cr & \Leftrightarrow 4x = 48000 \cr & \Leftrightarrow x = 12000. \cr}\)

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A certain amount earns simple Interest of Rs. 1,750/- after 7 years. Had the interest been 2% more, how much more interest would it have earned ?

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BANK PO Exam (Canara Bank) 2003 click here to view all questions

A certain amount earns simple Interest of Rs. 1,750/- after 7 years. Had the interest been 2% more, how much more interest would it have earned ?

ARs. 35/-

BRs. 350/-

CRs. 245/-

DCannot be determined

nithin ? undefined

To find out how much more interest would have been earned if the interest rate were 2% more,
we need to calculate the interest earned at the original rate and the interest earned at the increased rate.
Let's denote: - Original interest rate = \(R\) (in percentage)
- Principal amount = \(P\)
- Time period = \(T\) (in years)
- Original interest earned = \(I_1\)
- Interest earned at the increased rate = \(I_2\)
Given: - \(I_1 = Rs. 1,750\) - \(T = 7\) years We can use the formula for simple interest: \[I = \frac{P \times R \times T}{100}\] For the original interest rate: \[1750 = \frac{P \times R \times 7}{100}\] \[P \times R = \frac{1750 \times 100}{7}\] \[P \times R = 25000\] Now, if the interest rate were increased by 2%, the new rate would be \(R + 2\) (in percentage). For the increased interest rate: \[I_2 = \frac{P \times (R + 2) \times 7}{100}\] The difference in interest would be: \[\text{Difference} = I_2 - I_1\] Let's calculate \(I_2\) and the difference: \[I_2 = \frac{P \times (R + 2) \times 7}{100}\] \[= \frac{P \times (R \times 7 + 2 \times 7)}{100}\] \[= \frac{P \times (25000 + 2 \times 7)}{100}\] \[= \frac{P \times (25000 + 14)}{100}\] \[= \frac{P \times 25014}{100}\] \[= 250.14P\] Now, calculate the difference: \[\text{Difference} = I_2 - I_1\] \[= 250.14P - 1750\] We have the value of \(P\) from the earlier calculation: \[P \times R = 25000\] \[R = \frac{25000}{P}\] Substitute this value of \(R\) into the difference equation: \[\text{Difference} = 250.14P - 1750\] \[= 250.14P - 1750\] \[= 250.14 \times \frac{25000}{R} - 1750\] Now, we need to determine the value of \(R\) (original interest rate). However, it's not given, so we can't determine the exact difference. Therefore, the answer is option D: Cannot be determined.

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A seller allows a discount of 5% on a watch. If he allows a discount of 7%, he earns Rs.15 less in the profit. What is the marked price?

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INSURANCE EXAMS (NICL) 2013 click here to view all questions

A seller allows a discount of 5% on a watch. If he allows a discount of 7%, he earns Rs.15 less in the profit. What is the marked price?

ARs.697.50

BRs.712.50

CRs.750

DRs.817.50

Nithin ? undefined

Correct answer is: Rs.750

Explanation:

lf the marked price be x then,

\(= \left(7-5\right)\) % of x = 15

\(\implies \frac{x \times 2}{100} = 15\)

\(\implies \frac{1500}{2} = \text{ Rs.750}\)

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A dealer offers a discount of 10% on the marked price of an article and still makes a profit of 20%. If its marked price is Rs.800, then the cost price is:

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INSURANCE EXAMS (NICL) 2013 click here to view all questions

A dealer offers a discount of 10% on the marked price of an article and still makes a profit of 20%. If its marked price is Rs.800, then the cost price is:

ARs.600

BRs.700

CRs.800

DRs.900

Nithin ? undefined

Correct answer is: Rs.600

Explanation:

Marked Price = Rs.800
S.P. = \(\frac{800 \times 90}{100}\)= Rs.720

Therefore, C.P. = \(= \frac{100}{120} \times 720\)

= Rs.600

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The difference between a discount of 40% on Rs.500 and two successive discounts of 36% and 4% on the same amount is

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INSURANCE EXAMS (NICL) 2013 click here to view all questions

The difference between a discount of 40% on Rs.500 and two successive discounts of 36% and 4% on the same amount is

ARs.0

BRs.2

CRs.1.93

DRs.7.20

Nithin ? undefined

Correct answer is: Rs.7.20

Explanation:

Discount of 40% on Rs.500

\(= \frac{500 \times 40}{100}\)= Rs.200

and single discount per cent equivalent to 36% and 4%

\(= \left(r_{1}+r_{2}-\frac{r_{1}r_{2}}{100}\right)\%\)

\(= 36+4-\frac{36 \times 4}{100}=40-1.44 = \text{38.56%}\)

Therefore, Discount by 38.56% on 500

\(= \frac{38.56 \times 500}{100} = \text{Rs.192.80}\)

Hence, required difference = (200 - 192.80} = Rs.7. 20

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