A water tank has three taps A, B and C.Tap A, when opened, can fill the water tank alone in 4 hours. Tap B, when opened, can fill the water tank alone in 6 hours and tap C, when opened, can empty the water tank alone in 3 hours. If taps A, B and C are opened simultaneously how long will it take to fill the tank completely ?

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A water tank has three taps A, B and C.Tap A, when opened, can fill the water tank alone in 4 hours. Tap B, when opened, can fill the water tank alone in 6 hours and tap C, when opened, can empty the water tank alone in 3 hours. If taps A, B and C are opened simultaneously how long will it take to fill the tank completely ?

A10 hours

B17 hours

C18 hours

D12 hours

Akilesh Kharvi ? May 29 '2017 at 18:52

Anwer is : 12 hours

Explanation:

Part of the tank filled in 1 hour when all the taps are opened

= \(\frac{1}{4}+\frac{1}{6}-\frac{1}{3}\)

= \(\frac{3+2-4}{12}\)

=\(\frac{1}{12}\)

Hence, the tank will be filled in 12 hours.

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Anwer is : 12 hours Explanation: Part of the tank filled in 1 hour when all the taps are opened = \(\frac{1}{4}+\frac{1}{6}-\frac{1}{3}\) = \(\frac{3+2-4}{12}\) =\(\frac{1}{12}\) Hence, the tank will be filled in 12 hours. Akilesh Kharvi ? answered May 29 '2017 at 18:52 All Comments

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