A and B are two alloys of gold and copper prepared by mixing metals in the proportions 7 : 2 and 7 : 11 respectively. If equal quantities of the alloys are melted to form a third alloy C, proportion of gold and copper in C will be

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INSURANCE EXAMS (OIC) 2012 click here to view all questions

A and B are two alloys of gold and copper prepared by mixing metals in the proportions 7 : 2 and 7 : 11 respectively. If equal quantities of the alloys are melted to form a third alloy C, proportion of gold and copper in C will be

A5 : 7

B5 : 9

C9 : 5

D7 : 5

Nithin ? undefined

Correct answer is: 7 : 5

Explanation:

Gold in C = \(\left( \frac{7}{9} + \frac{7}{18} \right)\)

\(= \frac{21}{18} = \frac{7}{6}\)

Copper in C =  \( \left( \frac{2}{9} + \frac{11}{18} \right)\)

\(= \frac{15}{18} = \frac{5}{6}\)

Gold : Copper = \(\frac{7}{6} : \frac{5}{6}\)

= 7 : 5

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Correct answer is: 7 : 5 Explanation: Gold in C = \(\left( \frac{7}{9} + \frac{7}{18} \right)\) \(= \frac{21}{18} = \frac{7}{6}\) Copper in C =  \( \left( \frac{2}{9} + \frac{11}{18} \right)\) \(= \frac{15}{18} = \frac{5}{6}\) Gold : Copper = \(\frac{7}{6} : \frac{5}{6}\) = 7 : 5 Nithin ? answered undefined All Comments

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