To x litres of an x% solution of acid, y litres of water is added to get (x -10)% solution of acid. If x > 20, then value of y is

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INSURANCE EXAMS (OIC) 2012 click here to view all questions

To x litres of an x% solution of acid, y litres of water is added to get (x -10)% solution of acid. If x > 20, then value of y is

A$\frac{x^2}{100}$

B$\frac{10x}{x-10}$

C$\frac{10x}{x+10}$

D$\frac{10x^2}{x-10}$

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Correct answer: $\frac{10x}{x-10}$ Explanation: In litres of solution, Acid = $\frac{x^2}{100}$ Water = $x- \frac{x^2}{100}$ $\therefore \frac{\frac{x^2}{100}}{x+y} \times 100 = x-10$ $\implies \frac{x^2}{x-y} = x-10$ $\implies x^2 =y^2-10x-y(x-10)$ $\implies y = \frac{-10x}{x-10} = \frac{10x}{x-10}$ Nithin ? answered undefined All Comments

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