To x litres of an x% solution of acid, y litres of water is added to get (x -10)% solution of acid. If x > 20, then value of y is

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INSURANCE EXAMS (OIC) 2012 click here to view all questions

To x litres of an x% solution of acid, y litres of water is added to get (x -10)% solution of acid. If x > 20, then value of y is

A$\frac{x^2}{100}$

B$\frac{10x}{x-10}$

C$\frac{10x}{x+10}$

D$\frac{10x^2}{x-10}$

Nithin ? undefined

Correct answer: \(\frac{10x}{x-10}\)

Explanation:

In litres of solution,

Acid = \(\frac{x^2}{100}\)

Water = \(x- \frac{x^2}{100}\)

\(\therefore \frac{\frac{x^2}{100}}{x+y} \times 100 = x-10\)

\(\implies \frac{x^2}{x-y} = x-10\)

\(\implies x^2 =y^2-10x-y(x-10)\)

\(\implies y = \frac{-10x}{x-10} = \frac{10x}{x-10}\)

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Correct answer: \(\frac{10x}{x-10}\) Explanation: In litres of solution, Acid = \(\frac{x^2}{100}\) Water = \(x- \frac{x^2}{100}\) \(\therefore \frac{\frac{x^2}{100}}{x+y} \times 100 = x-10\) \(\implies \frac{x^2}{x-y} = x-10\) \(\implies x^2 =y^2-10x-y(x-10)\) \(\implies y = \frac{-10x}{x-10} = \frac{10x}{x-10}\) Nithin ? answered undefined All Comments

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