Two barrels contain a mixture of ethanol and gasoline. The content of the ethanol is 60% in the first barrel and 30% in the second barrel. In what ratio must the mixtures from the first and the second barrels be taken to form a mixture containing 50% ethanol ?

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Two barrels contain a mixture of ethanol and gasoline. The content of the ethanol is 60% in the first barrel and 30% in the second barrel. In what ratio must the mixtures from the first and the second barrels be taken to form a mixture containing 50% ethanol ?

A1 : 2

B2 : 1

C2 : 3

D3 : 2

Nithin ? undefined

Correct answer is: 2 : 1

Explanation:

By allegation,
Mixture-I Mixture-II
Therefore, Required ratio
\(= \frac{1}{5}:\frac{1}{10}\)

\(= 2:1\)

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Correct answer is: 2 : 1 Explanation: By allegation, Mixture-I Mixture-II Therefore, Required ratio \(= \frac{1}{5}:\frac{1}{10}\) \(= 2:1\) Nithin ? answered undefined All Comments

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