If the product of two successive positive integers is 7482.

Report

Report an issue

Name

Email

Message

Submit

Cancel

RRB TA Exam (Chennai) 2008 click here to view all questions

If the product of two successive positive integers is 7482. Which is the greater integer?

A87

B82

C84

D89

Nithin K ? Dec 4 '2016 at 10:14

Answer : 87

Explanation:

Given that \(x(x+1)=7482\)
\(x^2+x=7482\)
\(x^2+x-7482=0 \)
Solve by quadratic equation 

\((x-87)(x+86)=0\)

\(\therefore x=87 \text{ or } x=-86\)

\(\because \text{ the integers are positive the negative option is disregarded. So the answer is 87.}\)

View Answer

Discuss

A plot of 575 sq.ft is available at the rate of Rs.5500 per

Report

Report an issue

Name

Email

Message

Submit

Cancel

RRB TA Exam (Chennai) 2008 click here to view all questions

A plot of 575 sq.ft is available at the rate of Rs.5500 per sq.ft. If 25% of the total cost of the plot is to be paid for booking the plot. How much is the booking amount?

ARs.825750

BRs.790625

CRs.875250

DRs.735500

Nithin K ? Dec 4 '2016 at 9:53

Answer: Rs.790625

Explanation:

\(\text{Total cost of plot = Rs. 575} \times\text{ 5500 } = 3162500\)
\(\text{Booking amount =} \frac{3162500\times 25}{100}=258750\)
\(=Rs. 790625\)

View Answer

Discuss

At simple interest a sum of Rs.64 becomes Rs.83.20 in 2 yr.

Report

Report an issue

Name

Email

Message

Submit

Cancel

RRB TA Exam (Chennai) 2008 click here to view all questions

At simple interest a sum of Rs.64 becomes Rs.83.20 in 2 yr. What will Rs.86 become in 4 yr at the same rate of interest?

ARs.129.40

BRs.137.60

CRs.142.30

DRs.144.80

Nithin K ? Dec 3 '2016 at 19:47

Answer : Rs.137.60

Explanation:

Formula:    \(S.I. = \frac{P \times T \times R}{100}\)

P=Rs. 64,

S.I. = Rs. (83.20 - 64) = Rs. 19.20,

T = 2 years.

So, rate R = \(\frac{SI \times 100}{P \times T}\)=\(\frac{ (100 \times 19.20 ) \% }{64 \times 2} = 15\%                       \)

Now, P = Rs.86, R= 15%, T = 4 years.

S.I. = \(\frac{Rs ( 86 \times 15 \times 14 )}{100} = Rs. 51.60                      \)

View Answer

Discuss

If a man travels 160 km by car at the speed of 64 km/h and a

Report

Report an issue

Name

Email

Message

Submit

Cancel

RRB TA Exam (Chennai) 2008 click here to view all questions

If a man travels 160 km by car at the speed of 64 km/h and another 160 km at the speed of 80 km/h, the average speed for the whole journey is

A71.11

B81.11

C91.11

D61.11

Nithin K ? Dec 3 '2016 at 19:26

Answer : 71.11

Explanation:

Formula: 

\(Time = \frac{Distance}{speed} \)

\(\text{total time taken = (times taken for first 160km + times taken for next 160km)}\)
\(\text{total time taken }= \big(\frac{160}{64} + \frac{160}{80}\big)\)

\(=\frac{9}{2}\text{ hours }\)
\(\text{Time taken for 320 Km = 320 }\times \text{29=71.11km/hr}\)

View Answer

Discuss

in the equation 4050/sqrt(x), value of x is

Report

Report an issue

Name

Email

Message

Submit

Cancel

RRB TA Exam (Chennai) 2008 click here to view all questions

A49

B100

C81

D9

No answer description available for this question. Let us discuss.

View Answer

Discuss

The length of a rectangle is decreased by 10% and its

Report

Report an issue

Name

Email

Message

Submit

Cancel

RRB TA Exam (Chennai) 2008 click here to view all questions

The length of a rectangle is decreased by 10% and its breadth is increased by 10%. By what percent is its area changed?

A0%

B1%

C5%

D100%

Nithin K ? Dec 2 '2016 at 23:57

Answer is : 1%

Explanation:

When there is an increase in sides of a figure, the net increase in its area is

\(= x+y+\frac{xy}{100} \%\)

where x and y are length and breadth

given, length x decreased by 10. so, x =  -10.

breadth y increased by 10. so, y = 10.

percent is its area changed
\(= -10 + 10 + \frac{-10 \times10}{100}\% = -1 \%\)

\(\therefore \text{ percent of area decresed by 1%}\)

 

View Answer

Discuss

Successive discounts of 10% and 20% are equivalent to a

Report

Report an issue

Name

Email

Message

Submit

Cancel

RRB TA Exam (Chennai) 2008 click here to view all questions

Successive discounts of 10% and 20% are equivalent to a single discount of

A30%

B15%

C28%

D72%

Nithin K ? Dec 2 '2016 at 22:21

Answer is : 28%

Explanation:

Let marked price be 100. 
apply 10% discount 
\(\frac{10}{100}*100=10 \)   ......(i)

apply 20% discount 
\(\frac{20}{100}*90=18 \)   .......(ii)

Total discounts = (i) + (ii)

=10+18

=28 
discount percentage=\(\frac{28}{100}*100\)=28%

View Answer

Discuss